Whakaoti mō x
x=\frac{\log_{2}\left(\frac{3}{5}\right)}{4}-\frac{1}{2}\approx -0.684241399
Whakaoti mō x (complex solution)
x=\frac{\pi n_{1}i}{2\ln(2)}+\frac{\log_{2}\left(\frac{3}{20}\right)}{4}
n_{1}\in \mathrm{Z}
Graph
Tohaina
Kua tāruatia ki te papatopenga
100\times 2^{4x}=15
Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.
2^{4x}=\frac{3}{20}
Whakawehea ngā taha e rua ki te 100.
\log(2^{4x})=\log(\frac{3}{20})
Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.
4x\log(2)=\log(\frac{3}{20})
Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.
4x=\frac{\log(\frac{3}{20})}{\log(2)}
Whakawehea ngā taha e rua ki te \log(2).
4x=\log_{2}\left(\frac{3}{20}\right)
Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=\frac{\ln(\frac{3}{20})}{4\ln(2)}
Whakawehea ngā taha e rua ki te 4.
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