Whakaoti i te 10-0*1^2+12-0*2I+13-0*3I-5I=0

$$10-0 \cdot { 1 }^{ 2 } +12-0 \cdot 2I+13-0 \cdot 3I-5I = 0$$

Whakaoti mō I

$$I=7$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$10-0\times 1+12-0\times 2I+13-0\times 3I-5I=0$$

Whakareatia te 0 ki te 1, ka 0.

$$10-0+12-0\times 2I+13-0\times 3I-5I=0$$

Tangohia te 0 i te 10, ka 10.

$$10+12-0\times 2I+13-0\times 3I-5I=0$$

Tāpirihia te 10 ki te 12, ka 22.

$$22-0\times 2I+13-0\times 3I-5I=0$$

Whakareatia te 0 ki te 2, ka 0.

$$22-0I+13-0\times 3I-5I=0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$22-0+13-0\times 3I-5I=0$$

Tangohia te 0 i te 22, ka 22.

$$22+13-0\times 3I-5I=0$$

Tāpirihia te 22 ki te 13, ka 35.

$$35-0\times 3I-5I=0$$

Whakareatia te 0 ki te 3, ka 0.

$$35-0I-5I=0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$35-0-5I=0$$

Tangohia te 0 i te 35, ka 35.

$$35-5I=0$$

Tangohia te 35 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-5I=-35$$

Whakawehea ngā taha e rua ki te -5.

$$I=\frac{-35}{-5}$$

Whakawehea te -35 ki te -5, kia riro ko 7.

$$I=7$$