Whakaoti i te 10-(-3(x-7)+5x)+40=5(4-3x

$$10-(-3(x-7)+5x)+40=5(4-3x$$

Whakaoti mō x

$$x=-\frac{9}{13}\approx -0.692307692$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x-7.

$$10-\left(-3x+21+5x\right)+40=5\left(4-3x\right)$$

Pahekotia te -3x me 5x, ka 2x.

$$10-\left(2x+21\right)+40=5\left(4-3x\right)$$

Hei kimi i te tauaro o 2x+21, kimihia te tauaro o ia taurangi.

$$10-2x-21+40=5\left(4-3x\right)$$

Tangohia te 21 i te 10, ka -11.

$$-11-2x+40=5\left(4-3x\right)$$

Tāpirihia te -11 ki te 40, ka 29.

$$29-2x=5\left(4-3x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 4-3x.

$$29-2x=20-15x$$

Me tāpiri te 15x ki ngā taha e rua.

$$29-2x+15x=20$$

Pahekotia te -2x me 15x, ka 13x.

$$29+13x=20$$

Tangohia te 29 mai i ngā taha e rua.

$$13x=20-29$$

Tangohia te 29 i te 20, ka -9.

$$13x=-9$$

Whakawehea ngā taha e rua ki te 13.

$$x=\frac{-9}{13}$$

Ka taea te hautanga \frac{-9}{13} te tuhi anō ko -\frac{9}{13} mā te tango i te tohu tōraro.

$$x=-\frac{9}{13}$$