Whakaoti i te 10(1000-x)(1+02%x)geq12x

$$10(1000-x)(1+02 \% x) \geq 12x$$

Whakaoti mō x

$$x\leq \frac{5000}{11}$$

Ngā Upane Otinga

Whakahekea te hautanga \frac{2}{100} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$10\left(1000-x\right)\left(1+0\times \frac{1}{50}x\right)\geq 12x$$

Whakareatia te 0 ki te \frac{1}{50}, ka 0.

$$10\left(1000-x\right)\left(1+0x\right)\geq 12x$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$10\left(1000-x\right)\left(1+0\right)\geq 12x$$

Tāpirihia te 1 ki te 0, ka 1.

$$10\left(1000-x\right)\times 1\geq 12x$$

Whakareatia te 10 ki te 1, ka 10.

$$10\left(1000-x\right)\geq 12x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10 ki te 1000-x.

$$10000-10x\geq 12x$$

Tangohia te 12x mai i ngā taha e rua.

$$10000-10x-12x\geq 0$$

Pahekotia te -10x me -12x, ka -22x.

$$10000-22x\geq 0$$

Tangohia te 10000 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-22x\geq -10000$$

Whakawehea ngā taha e rua ki te -22. I te mea he tōraro a -22, ka huri te ahunga koreōrite.

$$x\leq \frac{-10000}{-22}$$

Whakahekea te hautanga \frac{-10000}{-22} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x\leq \frac{5000}{11}$$