Whakaoti i te 10-(4-3x)+5x=6(2x-1)+8

$$10 - ( 4 - 3 x ) + 5 x = 6 ( 2 x - 1 ) + 8$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 4-3x, kimihia te tauaro o ia taurangi.

$$10-4-\left(-3x\right)+5x=6\left(2x-1\right)+8$$

Ko te tauaro o -3x ko 3x.

$$10-4+3x+5x=6\left(2x-1\right)+8$$

Tangohia te 4 i te 10, ka 6.

$$6+3x+5x=6\left(2x-1\right)+8$$

Pahekotia te 3x me 5x, ka 8x.

$$6+8x=6\left(2x-1\right)+8$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te 2x-1.

$$6+8x=12x-6+8$$

Tāpirihia te -6 ki te 8, ka 2.

$$6+8x=12x+2$$

Tangohia te 12x mai i ngā taha e rua.

$$6+8x-12x=2$$

Pahekotia te 8x me -12x, ka -4x.

$$6-4x=2$$

Tangohia te 6 mai i ngā taha e rua.

$$-4x=2-6$$

Tangohia te 6 i te 2, ka -4.

$$-4x=-4$$

Whakawehea ngā taha e rua ki te -4.

$$x=\frac{-4}{-4}$$

Whakawehea te -4 ki te -4, kia riro ko 1.

$$x=1$$