Whakaoti i te 10x^2+3=633

$$10 { x }^{ 2 } +3=633$$

Whakaoti mō x

$$x=3\sqrt{7}\approx 7.937253933$$

$$x=-3\sqrt{7}\approx -7.937253933$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 3 mai i ngā taha e rua.

$$10x^{2}=633-3$$

Tangohia te 3 i te 633, ka 630.

$$10x^{2}=630$$

Whakawehea ngā taha e rua ki te 10.

$$x^{2}=\frac{630}{10}$$

Whakawehea te 630 ki te 10, kia riro ko 63.

$$x^{2}=63$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=3\sqrt{7} x=-3\sqrt{7}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 633 mai i ngā taha e rua.

$$10x^{2}+3-633=0$$

Tangohia te 633 i te 3, ka -630.

$$10x^{2}-630=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 10 mō a, 0 mō b, me -630 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 10\left(-630\right)}}{2\times 10}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 10\left(-630\right)}}{2\times 10}$$

Whakareatia -4 ki te 10.

$$x=\frac{0±\sqrt{-40\left(-630\right)}}{2\times 10}$$

Whakareatia -40 ki te -630.

$$x=\frac{0±\sqrt{25200}}{2\times 10}$$

Tuhia te pūtakerua o te 25200.

$$x=\frac{0±60\sqrt{7}}{2\times 10}$$

Whakareatia 2 ki te 10.

$$x=\frac{0±60\sqrt{7}}{20}$$

Nā, me whakaoti te whārite x=\frac{0±60\sqrt{7}}{20} ina he tāpiri te ±.

$$x=3\sqrt{7}$$

Nā, me whakaoti te whārite x=\frac{0±60\sqrt{7}}{20} ina he tango te ±.

$$x=-3\sqrt{7}$$

Kua oti te whārite te whakatau.

$$x=3\sqrt{7} x=-3\sqrt{7}$$