Whakaoti i te 10^1-x=5

$$10 ^ { 1 - x } = 5$$

Whakaoti mō x

$$x=\log_{10}\left(2\right)\approx 0.301029996$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$10^{-x+1}=5$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(10^{-x+1})=\log(5)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(-x+1\right)\log(10)=\log(5)$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$-x=\log(5)-1$$

Whakawehea ngā taha e rua ki te -1.

$$x=\frac{\log(5)-1}{-1}$$

Whakaoti mō x (complex solution)

$$x=-\frac{2\pi n_{1}i}{\ln(10)}+\log_{10}\left(2\right)$$

$$n_{1}\in \mathrm{Z}$$