Whakaoti i te 1.024=h^2

$$1.024 = h ^ { 2 }$$

Whakaoti mō h

$$h = \frac{8 \sqrt{10}}{25} \approx 1.011928851$$

$$h = -\frac{8 \sqrt{10}}{25} \approx -1.011928851$$

Ngā Upane mā te Kimi Pūtakerua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$h^{2}=1.024$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$h=\frac{8\sqrt{10}}{25} h=-\frac{8\sqrt{10}}{25}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$h^{2}=1.024$$

Tangohia te 1.024 mai i ngā taha e rua.

$$h^{2}-1.024=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1.024 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$h=\frac{0±\sqrt{0^{2}-4\left(-1.024\right)}}{2}$$

Pūrua 0.

$$h=\frac{0±\sqrt{-4\left(-1.024\right)}}{2}$$

Whakareatia -4 ki te -1.024.

$$h=\frac{0±\sqrt{4.096}}{2}$$

Tuhia te pūtakerua o te 4.096.

$$h=\frac{0±\frac{16\sqrt{10}}{25}}{2}$$

Nā, me whakaoti te whārite h=\frac{0±\frac{16\sqrt{10}}{25}}{2} ina he tāpiri te ±.

$$h=\frac{8\sqrt{10}}{25}$$

Nā, me whakaoti te whārite h=\frac{0±\frac{16\sqrt{10}}{25}}{2} ina he tango te ±.

$$h=-\frac{8\sqrt{10}}{25}$$

Kua oti te whārite te whakatau.

$$h=\frac{8\sqrt{10}}{25} h=-\frac{8\sqrt{10}}{25}$$