Whakaoti i te 1-9/5x=2/5

$$1- \frac{ 9 }{ 5 } x= \frac{ 2 }{ 5 }$$

Whakaoti mō x

$$x=\frac{1}{3}\approx 0.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 1 mai i ngā taha e rua.

$$-\frac{9}{5}x=\frac{2}{5}-1$$

Me tahuri te 1 ki te hautau \frac{5}{5}.

$$-\frac{9}{5}x=\frac{2}{5}-\frac{5}{5}$$

Tā te mea he rite te tauraro o \frac{2}{5} me \frac{5}{5}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{9}{5}x=\frac{2-5}{5}$$

Tangohia te 5 i te 2, ka -3.

$$-\frac{9}{5}x=-\frac{3}{5}$$

Me whakarea ngā taha e rua ki te -\frac{5}{9}, te tau utu o -\frac{9}{5}.

$$x=-\frac{3}{5}\left(-\frac{5}{9}\right)$$

Me whakarea te -\frac{3}{5} ki te -\frac{5}{9} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{-3\left(-5\right)}{5\times 9}$$

Mahia ngā whakarea i roto i te hautanga \frac{-3\left(-5\right)}{5\times 9}.

$$x=\frac{15}{45}$$

Whakahekea te hautanga \frac{15}{45} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 15.

$$x=\frac{1}{3}$$