Whakaoti i te 1,1*2,5+1,1^2:11

$$1,1 \cdot 2,5 + 1,1 ^ { 2 } : 11$$

Kōmaka

$$\frac{1}{11},1,2,6$$

Ngā Upane Otinga

Whakareatia te 1 ki te 2, ka 2.

$$sort(1,2,5+1,\frac{1^{2}}{11})$$

Tāpirihia te 5 ki te 1, ka 6.

$$sort(1,2,6,\frac{1^{2}}{11})$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$sort(1,2,6,\frac{1}{11})$$

Tahuritia ngā tau ā-ira i te rārangi 1,2,6,\frac{1}{11} ki ngā hautanga.

$$1,2,6,\frac{1}{11}$$

Hei kōmaka i te rārangi, me tīmata mai i tētahi huānga 1 kotahi.

$$1$$

Me kōkuhu te 2 ki te tauwāhi tika i te rārangi hōu.

$$1,2$$

Me kōkuhu te 6 ki te tauwāhi tika i te rārangi hōu.

$$1,2,6$$

Me kōkuhu te \frac{1}{11} ki te tauwāhi tika i te rārangi hōu.

$$\frac{1}{11},1,2,6$$

Aromātai

$$1,2,6,\frac{1}{11}$$