Whakaoti i te 1+e(2x)-2xe(2x)

$$1+e(2x)-2xe(2x)$$

Aromātai

$$1+2ex-4ex^{2}$$

Ngā Upane Otinga

Whakareatia te x ki te x, ka x^{2}.

$$1+e\times 2x-2x^{2}e\times 2$$

Whakareatia te 2 ki te 2, ka 4.

$$1+e\times 2x-4x^{2}e$$

Kimi Pārōnaki e ai ki x

$$2e-8ex$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Whakareatia te x ki te x, ka x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(1+e\times 2x-2x^{2}e\times 2)$$

Whakareatia te 2 ki te 2, ka 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(1+e\times 2x-4x^{2}e)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2ex^{1-1}+2\left(-4e\right)x^{2-1}$$

Tango 1 mai i 1.

$$2ex^{0}+2\left(-4e\right)x^{2-1}$$

Whakareatia 2 ki te -4e.

$$2ex^{0}+\left(-8e\right)x^{2-1}$$

Tango 1 mai i 2.

$$2ex^{0}+\left(-8e\right)x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$2ex^{0}+\left(-8e\right)x$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$2e\times 1+\left(-8e\right)x$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$2e+\left(-8e\right)x$$