Whakaoti i te 1m=mm

$$1 m = m m$$

Whakaoti mō m

$$m=1$$

$$m=0$$

Ngā Upane Whakamahi Tauwehe

Whakareatia te m ki te m, ka m^{2}.

$$1m=m^{2}$$

Tangohia te m^{2} mai i ngā taha e rua.

$$1m-m^{2}=0$$

Whakaraupapatia anō ngā kīanga tau.

$$-m^{2}+m=0$$

Tauwehea te m.

$$m\left(-m+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te m=0 me te -m+1=0.

$$m=0 m=1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te m ki te m, ka m^{2}.

$$1m=m^{2}$$

Tangohia te m^{2} mai i ngā taha e rua.

$$1m-m^{2}=0$$

Whakaraupapatia anō ngā kīanga tau.

$$-m^{2}+m=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 1 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{-1±\sqrt{1^{2}}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 1^{2}.

$$m=\frac{-1±1}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$m=\frac{-1±1}{-2}$$

Nā, me whakaoti te whārite m=\frac{-1±1}{-2} ina he tāpiri te ±. Tāpiri -1 ki te 1.

$$m=\frac{0}{-2}$$

Whakawehe 0 ki te -2.

$$m=0$$

Nā, me whakaoti te whārite m=\frac{-1±1}{-2} ina he tango te ±. Tango 1 mai i -1.

$$m=-\frac{2}{-2}$$

Whakawehe -2 ki te -2.

$$m=1$$

Kua oti te whārite te whakatau.

$$m=0 m=1$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakareatia te m ki te m, ka m^{2}.

$$1m=m^{2}$$

Tangohia te m^{2} mai i ngā taha e rua.

$$1m-m^{2}=0$$

Whakaraupapatia anō ngā kīanga tau.

$$-m^{2}+m=0$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-m^{2}+m}{-1}=\frac{0}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$m^{2}+\frac{1}{-1}m=\frac{0}{-1}$$

Whakawehe 1 ki te -1.

$$m^{2}-m=\frac{0}{-1}$$

Whakawehe 0 ki te -1.

$$m^{2}-m=0$$

Whakawehea te -1, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{1}{2}. Nā, tāpiria te pūrua o te -\frac{1}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$m^{2}-m+\left(-\frac{1}{2}\right)^{2}=\left(-\frac{1}{2}\right)^{2}$$

Pūruatia -\frac{1}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$m^{2}-m+\frac{1}{4}=\frac{1}{4}$$

Tauwehea m^{2}-m+\frac{1}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(m-\frac{1}{2}\right)^{2}=\frac{1}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(m-\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}}$$

Whakarūnātia.

$$m-\frac{1}{2}=\frac{1}{2} m-\frac{1}{2}=-\frac{1}{2}$$

Me tāpiri \frac{1}{2} ki ngā taha e rua o te whārite.

$$m=1 m=0$$