Whakaoti i te 1-3*(5x-2)=x-(x-2)*3

$$1 - 3 \cdot ( 5 x - 2 ) = x - ( x - 2 ) \cdot 3$$

Whakaoti mō x

$$x=\frac{1}{13}\approx 0.076923077$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 5x-2.

$$1-15x+6=x-\left(x-2\right)\times 3$$

Tāpirihia te 1 ki te 6, ka 7.

$$7-15x=x-\left(x-2\right)\times 3$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te 3.

$$7-15x=x-\left(3x-6\right)$$

Hei kimi i te tauaro o 3x-6, kimihia te tauaro o ia taurangi.

$$7-15x=x-3x-\left(-6\right)$$

Ko te tauaro o -6 ko 6.

$$7-15x=x-3x+6$$

Pahekotia te x me -3x, ka -2x.

$$7-15x=-2x+6$$

Me tāpiri te 2x ki ngā taha e rua.

$$7-15x+2x=6$$

Pahekotia te -15x me 2x, ka -13x.

$$7-13x=6$$

Tangohia te 7 mai i ngā taha e rua.

$$-13x=6-7$$

Tangohia te 7 i te 6, ka -1.

$$-13x=-1$$

Whakawehea ngā taha e rua ki te -13.

$$x=\frac{-1}{-13}$$

Ka taea te hautanga \frac{-1}{-13} te whakamāmā ki te \frac{1}{13} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{1}{13}$$