Whakaoti i te 1^2+1^2=C^2

$$1 ^ { 2 } + 1 ^ { 2 } = C ^ { 2 }$$

Whakaoti mō C

$$C=\sqrt{2}\approx 1.414213562$$

$$C=-\sqrt{2}\approx -1.414213562$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$1+1^{2}=C^{2}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$1+1=C^{2}$$

Tāpirihia te 1 ki te 1, ka 2.

$$2=C^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$C^{2}=2$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$C=\sqrt{2} C=-\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$1+1^{2}=C^{2}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$1+1=C^{2}$$

Tāpirihia te 1 ki te 1, ka 2.

$$2=C^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$C^{2}=2$$

Tangohia te 2 mai i ngā taha e rua.

$$C^{2}-2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$C=\frac{0±\sqrt{0^{2}-4\left(-2\right)}}{2}$$

Pūrua 0.

$$C=\frac{0±\sqrt{-4\left(-2\right)}}{2}$$

Whakareatia -4 ki te -2.

$$C=\frac{0±\sqrt{8}}{2}$$

Tuhia te pūtakerua o te 8.

$$C=\frac{0±2\sqrt{2}}{2}$$

Nā, me whakaoti te whārite C=\frac{0±2\sqrt{2}}{2} ina he tāpiri te ±.

$$C=\sqrt{2}$$

Nā, me whakaoti te whārite C=\frac{0±2\sqrt{2}}{2} ina he tango te ±.

$$C=-\sqrt{2}$$

Kua oti te whārite te whakatau.

$$C=\sqrt{2} C=-\sqrt{2}$$