Whakaoti i te 1:y=-1/4x-3

$$1 : y = - \frac { 1 } { 4 } x - 3$$

Whakaoti mō x

$$x=-12-\frac{4}{y}$$

$$y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 4y, arā, te tauraro pātahi he tino iti rawa te kitea o y,4.

$$4=-\frac{1}{4}x\times 4y+4y\left(-3\right)$$

Whakareatia te -\frac{1}{4} ki te 4, ka -1.

$$4=-xy+4y\left(-3\right)$$

Whakareatia te 4 ki te -3, ka -12.

$$4=-xy-12y$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-xy-12y=4$$

Me tāpiri te 12y ki ngā taha e rua.

$$-xy=4+12y$$

He hanga arowhānui tō te whārite.

$$\left(-y\right)x=12y+4$$

Whakawehea ngā taha e rua ki te -y.

$$\frac{\left(-y\right)x}{-y}=\frac{12y+4}{-y}$$

Mā te whakawehe ki te -y ka wetekia te whakareanga ki te -y.

$$x=\frac{12y+4}{-y}$$

Whakawehe 4+12y ki te -y.

$$x=-12-\frac{4}{y}$$

Whakaoti mō y

$$y=-\frac{4}{x+12}$$

$$x\neq -12$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 4y, arā, te tauraro pātahi he tino iti rawa te kitea o y,4.

$$4=-\frac{1}{4}x\times 4y+4y\left(-3\right)$$

Whakareatia te -\frac{1}{4} ki te 4, ka -1.

$$4=-xy+4y\left(-3\right)$$

Whakareatia te 4 ki te -3, ka -12.

$$4=-xy-12y$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-xy-12y=4$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(-x-12\right)y=4$$

Whakawehea ngā taha e rua ki te -x-12.

$$\frac{\left(-x-12\right)y}{-x-12}=\frac{4}{-x-12}$$

Mā te whakawehe ki te -x-12 ka wetekia te whakareanga ki te -x-12.

$$y=\frac{4}{-x-12}$$

Whakawehe 4 ki te -x-12.

$$y=-\frac{4}{x+12}$$

Tē taea kia ōrite te tāupe y ki 0.

$$y=-\frac{4}{x+12}\text{, }y\neq 0$$