Whakaoti i te 1:f(x)=1/1+5x

$$1 : f ( x ) = \frac { 1 } { 1 + 5 x }$$

Whakaoti mō f

$$f=x\left(5x+1\right)$$

$$x\neq -\frac{1}{5}\text{ and }x\neq 0$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe f ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te f\left(5x+1\right), arā, te tauraro pātahi he tino iti rawa te kitea o f,1+5x.

$$\left(5x+1\right)\times 1x=f$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5x+1 ki te 1.

$$\left(5x+1\right)x=f$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5x+1 ki te x.

$$5x^{2}+x=f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$f=5x^{2}+x$$

Tē taea kia ōrite te tāupe f ki 0.

$$f=5x^{2}+x\text{, }f\neq 0$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{20f+1}-1}{10}$$

$$x=\frac{-\sqrt{20f+1}-1}{10}\text{, }f\neq 0$$

Whakaoti mō x

$$x=\frac{\sqrt{20f+1}-1}{10}$$

$$x=\frac{-\sqrt{20f+1}-1}{10}\text{, }f\neq 0\text{ and }f\geq -\frac{1}{20}$$