Whakaoti i te 1/3-1/2m=16m+7/9

$$1 / 3 - 1 / 2 m = 16 m + 7 / 9$$

Whakaoti mō m

$$m=-\frac{8}{297}\approx -0.026936027$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 16m mai i ngā taha e rua.

$$\frac{1}{3}-\frac{1}{2}m-16m=\frac{7}{9}$$

Pahekotia te -\frac{1}{2}m me -16m, ka -\frac{33}{2}m.

$$\frac{1}{3}-\frac{33}{2}m=\frac{7}{9}$$

Tangohia te \frac{1}{3} mai i ngā taha e rua.

$$-\frac{33}{2}m=\frac{7}{9}-\frac{1}{3}$$

Ko te maha noa iti rawa atu o 9 me 3 ko 9. Me tahuri \frac{7}{9} me \frac{1}{3} ki te hautau me te tautūnga 9.

$$-\frac{33}{2}m=\frac{7}{9}-\frac{3}{9}$$

Tā te mea he rite te tauraro o \frac{7}{9} me \frac{3}{9}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{33}{2}m=\frac{7-3}{9}$$

Tangohia te 3 i te 7, ka 4.

$$-\frac{33}{2}m=\frac{4}{9}$$

Me whakarea ngā taha e rua ki te -\frac{2}{33}, te tau utu o -\frac{33}{2}.

$$m=\frac{4}{9}\left(-\frac{2}{33}\right)$$

Me whakarea te \frac{4}{9} ki te -\frac{2}{33} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$m=\frac{4\left(-2\right)}{9\times 33}$$

Mahia ngā whakarea i roto i te hautanga \frac{4\left(-2\right)}{9\times 33}.

$$m=\frac{-8}{297}$$

Ka taea te hautanga \frac{-8}{297} te tuhi anō ko -\frac{8}{297} mā te tango i te tohu tōraro.

$$m=-\frac{8}{297}$$