Whakaoti i te 1+x^2=2

$$1 + x ^ { 2 } = 2$$

Whakaoti mō x

$$x=1$$

$$x=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 2 mai i ngā taha e rua.

$$1+x^{2}-2=0$$

Tangohia te 2 i te 1, ka -1.

$$-1+x^{2}=0$$

Whakaarohia te -1+x^{2}. Tuhia anō te -1+x^{2} hei x^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-1\right)\left(x+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-1=0 me te x+1=0.

$$x=1 x=-1$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}=2-1$$

Tangohia te 1 i te 2, ka 1.

$$x^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=1 x=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 2 mai i ngā taha e rua.

$$1+x^{2}-2=0$$

Tangohia te 2 i te 1, ka -1.

$$-1+x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$x^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$x=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$x=\frac{0±2}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$x=1$$

Nā, me whakaoti te whārite x=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$x=-1$$

Kua oti te whārite te whakatau.

$$x=1 x=-1$$