Whakaoti i te 1+2(-x+2)-1=-(x+3)-1

$$1 + 2 ( - x + 2 ) - 1 = - ( x + 3 ) - 1$$

Whakaoti mō x

$$x=8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te -x+2.

$$1+2\left(-x\right)+4-1=-\left(x+3\right)-1$$

Tāpirihia te 1 ki te 4, ka 5.

$$5+2\left(-x\right)-1=-\left(x+3\right)-1$$

Tangohia te 1 i te 5, ka 4.

$$4+2\left(-x\right)=-\left(x+3\right)-1$$

Hei kimi i te tauaro o x+3, kimihia te tauaro o ia taurangi.

$$4+2\left(-x\right)=-x-3-1$$

Tangohia te 1 i te -3, ka -4.

$$4+2\left(-x\right)=-x-4$$

Me tāpiri te x ki ngā taha e rua.

$$4+2\left(-x\right)+x=-4$$

Tangohia te 4 mai i ngā taha e rua.

$$2\left(-x\right)+x=-4-4$$

Tangohia te 4 i te -4, ka -8.

$$2\left(-x\right)+x=-8$$

Whakareatia te 2 ki te -1, ka -2.

$$-2x+x=-8$$

Pahekotia te -2x me x, ka -x.

$$-x=-8$$

Me whakarea ngā taha e rua ki te -1.

$$x=8$$