Whakaoti i te 1+(3-x)^2=x^2

$$1 + ( 3 - x ) ^ { 2 } = x ^ { 2 }$$

Whakaoti mō x

$$x = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(3-x\right)^{2}.

$$1+9-6x+x^{2}=x^{2}$$

Tāpirihia te 1 ki te 9, ka 10.

$$10-6x+x^{2}=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$10-6x+x^{2}-x^{2}=0$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$10-6x=0$$

Tangohia te 10 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-6x=-10$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{-10}{-6}$$

Whakahekea te hautanga \frac{-10}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{5}{3}$$