Whakaoti i te 1+[2x(x-1/2)-(1-x)-2x^2]^3>x+13

$$1 + [ 2 x ( x - \frac { 1 } { 2 } ) - ( 1 - x ) - 2 x ^ { 2 } ] ^ { 3 } > x + 13$$

Whakaoti mō x

$$x<-13$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 2x ki te x-\frac{1}{2}.

$$1+\left(2x^{2}-x-\left(1-x\right)-2x^{2}\right)^{3}>x+13$$

Hei kimi i te tauaro o 1-x, kimihia te tauaro o ia taurangi.

$$1+\left(2x^{2}-x-1+x-2x^{2}\right)^{3}>x+13$$

Pahekotia te -x me x, ka 0.

$$1+\left(2x^{2}-1-2x^{2}\right)^{3}>x+13$$

Pahekotia te 2x^{2} me -2x^{2}, ka 0.

$$1+\left(-1\right)^{3}>x+13$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$1-1>x+13$$

Tangohia te 1 i te 1, ka 0.

$$0>x+13$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa. Ka huri tēnei i te aronga o te tohu.

$$x+13<0$$

Tangohia te 13 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x<-13$$