Whakaoti i te 0528(1-95x)-051(1-5x)=049(1-5x)-049(1-95x)

$$0528(1-95x)-051(1-5x)=049(1-5x)-049(1-95x)$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

Ngā Upane Otinga

Whakareatia te 0 ki te 528, ka 0.

$$0\left(1-95x\right)-0\times 51\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0-0\times 51\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 51, ka 0.

$$0-0\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0-0=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$0=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 49, ka 0.

$$0=0\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 49, ka 0.

$$0=0-0\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0-0$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{C}$$

Whakaoti mō x

$$x\in \mathrm{R}$$

Ngā Upane Otinga

Whakareatia te 0 ki te 528, ka 0.

$$0\left(1-95x\right)-0\times 51\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0-0\times 51\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 51, ka 0.

$$0-0\left(1-5x\right)=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0-0=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$0=0\times 49\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 49, ka 0.

$$0=0\left(1-5x\right)-0\times 49\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0-0\times 49\left(1-95x\right)$$

Whakareatia te 0 ki te 49, ka 0.

$$0=0-0\left(1-95x\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0-0$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$