Whakaoti i te 009(x+30)=[03(x+30)]^2/x+50

$$009 ( x + 30 ) = \frac { [ 03 ( x + 30 ) ] ^ { 2 } } { x + 50 }$$

Whakaoti mō x

$$x\neq -50$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe x ki -50 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+50.

$$0\times 0\times 9\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 9\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Whakareatia te 0 ki te 9, ka 0.

$$0\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=\left(0\times 3\left(x+30\right)\right)^{2}$$

Whakareatia te 0 ki te 3, ka 0.

$$0=\left(0\left(x+30\right)\right)^{2}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0^{2}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$

Tē taea kia ōrite te tāupe x ki -50.

$$x\in \mathrm{R}\setminus -50$$