Whakaoti i te 00058*0347*(1-x)=left(2*0347right)^2div10

$$00058 \times 0347 \times (1-x)= { \left(2 \times 0347 \right) }^{ 2 } \div 10$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

Ngā Upane Otinga

Whakareatia ngā taha e rua o te whārite ki te 10.

$$0\times 0\times 0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 58, ka 0.

$$0\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 347, ka 0.

$$0\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 2 ki te 0, ka 0.

$$0=\left(0\times 347\right)^{2}$$

Whakareatia te 0 ki te 347, ka 0.

$$0=0^{2}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{C}$$

Whakaoti mō x

$$x\in \mathrm{R}$$

Ngā Upane Otinga

Whakareatia ngā taha e rua o te whārite ki te 10.

$$0\times 0\times 0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 58\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 58, ka 0.

$$0\times 0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 0, ka 0.

$$0\times 347\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 0 ki te 347, ka 0.

$$0\left(1-x\right)=\left(2\times 0\times 347\right)^{2}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=\left(2\times 0\times 347\right)^{2}$$

Whakareatia te 2 ki te 0, ka 0.

$$0=\left(0\times 347\right)^{2}$$

Whakareatia te 0 ki te 347, ka 0.

$$0=0^{2}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$