Whakaoti i te 0=10-98x^2

$$0=10-98 { x }^{ 2 }$$

Whakaoti mō x

$$x=\frac{\sqrt{5}}{7}\approx 0.319438282$$

$$x=-\frac{\sqrt{5}}{7}\approx -0.319438282$$

Ngā Upane mā te Kimi Pūtakerua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$10-98x^{2}=0$$

Tangohia te 10 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-98x^{2}=-10$$

Whakawehea ngā taha e rua ki te -98.

$$x^{2}=\frac{-10}{-98}$$

Whakahekea te hautanga \frac{-10}{-98} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x^{2}=\frac{5}{49}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{5}}{7} x=-\frac{\sqrt{5}}{7}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$10-98x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-98x^{2}+10=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -98 mō a, 0 mō b, me 10 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-98\right)\times 10}}{2\left(-98\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-98\right)\times 10}}{2\left(-98\right)}$$

Whakareatia -4 ki te -98.

$$x=\frac{0±\sqrt{392\times 10}}{2\left(-98\right)}$$

Whakareatia 392 ki te 10.

$$x=\frac{0±\sqrt{3920}}{2\left(-98\right)}$$

Tuhia te pūtakerua o te 3920.

$$x=\frac{0±28\sqrt{5}}{2\left(-98\right)}$$

Whakareatia 2 ki te -98.

$$x=\frac{0±28\sqrt{5}}{-196}$$

Nā, me whakaoti te whārite x=\frac{0±28\sqrt{5}}{-196} ina he tāpiri te ±.

$$x=-\frac{\sqrt{5}}{7}$$

Nā, me whakaoti te whārite x=\frac{0±28\sqrt{5}}{-196} ina he tango te ±.

$$x=\frac{\sqrt{5}}{7}$$

Kua oti te whārite te whakatau.

$$x=-\frac{\sqrt{5}}{7} x=\frac{\sqrt{5}}{7}$$