Whakaoti i te 0=x^2pi

$$0 = x ^ { 2 } \pi$$

Whakaoti mō x

$$x=0$$

Ngā Upane mā te Kimi Pūtakerua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}\pi =0$$

Whakawehea ngā taha e rua ki te \pi .

$$\frac{\pi x^{2}}{\pi }=\frac{0}{\pi }$$

Mā te whakawehe ki te \pi ka wetekia te whakareanga ki te \pi .

$$x^{2}=\frac{0}{\pi }$$

Whakawehe 0 ki te \pi .

$$x^{2}=0$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=0 x=0$$

Kua oti te whārite te whakatau. He ōrite ngā whakatau.

$$x=0$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}\pi =0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$\pi x^{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi \pi mō a, 0 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2\pi }$$

Tuhia te pūtakerua o te 0^{2}.

$$x=\frac{0±0}{2\pi }$$

Whakareatia 2 ki te \pi .

$$x=\frac{0}{2\pi }$$

Whakawehe 0 ki te 2\pi .

$$x=0$$