Whakaoti i te 0=20-p^2

$$0 = 20 - p ^ { 2 }$$

Whakaoti mō p

$$p=2\sqrt{5}\approx 4.472135955$$

$$p=-2\sqrt{5}\approx -4.472135955$$

Ngā Upane mā te Kimi Pūtakerua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$20-p^{2}=0$$

Tangohia te 20 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-p^{2}=-20$$

Whakawehea ngā taha e rua ki te -1.

$$p^{2}=\frac{-20}{-1}$$

Ka taea te hautanga \frac{-20}{-1} te whakamāmā ki te 20 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$p^{2}=20$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$p=2\sqrt{5} p=-2\sqrt{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$20-p^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-p^{2}+20=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 0 mō b, me 20 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$p=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 20}}{2\left(-1\right)}$$

Pūrua 0.

$$p=\frac{0±\sqrt{-4\left(-1\right)\times 20}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$p=\frac{0±\sqrt{4\times 20}}{2\left(-1\right)}$$

Whakareatia 4 ki te 20.

$$p=\frac{0±\sqrt{80}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 80.

$$p=\frac{0±4\sqrt{5}}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$p=\frac{0±4\sqrt{5}}{-2}$$

Nā, me whakaoti te whārite p=\frac{0±4\sqrt{5}}{-2} ina he tāpiri te ±.

$$p=-2\sqrt{5}$$

Nā, me whakaoti te whārite p=\frac{0±4\sqrt{5}}{-2} ina he tango te ±.

$$p=2\sqrt{5}$$

Kua oti te whārite te whakatau.

$$p=-2\sqrt{5} p=2\sqrt{5}$$