Whakaoti i te 0=100+3d-5t^2

$$0 = 100 + 3 d - 5 t ^ { 2 }$$

Whakaoti mō d

$$d=\frac{5\left(t^{2}-20\right)}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$100+3d-5t^{2}=0$$

Tangohia te 100 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$3d-5t^{2}=-100$$

Me tāpiri te 5t^{2} ki ngā taha e rua.

$$3d=-100+5t^{2}$$

He hanga arowhānui tō te whārite.

$$3d=5t^{2}-100$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3d}{3}=\frac{5t^{2}-100}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$d=\frac{5t^{2}-100}{3}$$

Whakaoti mō t (complex solution)

$$t=-\frac{\sqrt{15d+500}}{5}$$

$$t=\frac{\sqrt{15d+500}}{5}$$

Whakaoti mō t

$$t=\frac{\sqrt{15d+500}}{5}$$

$$t=-\frac{\sqrt{15d+500}}{5}\text{, }d\geq -\frac{100}{3}$$