Whakaoti i te 0=0.1x^4-2x^2+6.4

$$0 = 0.1 x ^ { 4 } - 2 x ^ { 2 } + 6.4$$

Whakaoti mō x

$$x=-4$$

$$x=4$$

$$x=2$$

$$x=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$0.1x^{4}-2x^{2}+6.4=0$$

Whakakapia te t mō te x^{2}.

$$0.1t^{2}-2t+6.4=0$$

Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 0.1 mō te a, te -2 mō te b, me te 6.4 mō te c i te ture pūrua.

$$t=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 0.1\times 6.4}}{0.1\times 2}$$

Mahia ngā tātaitai.

$$t=\frac{2±\frac{6}{5}}{0.2}$$

Whakaotia te whārite t=\frac{2±\frac{6}{5}}{0.2} ina he tōrunga te ±, ina he tōraro te ±.

$$t=16 t=4$$

I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō ia t.

$$x=4 x=-4 x=2 x=-2$$