Whakaoti i te 0=2/2H125+10(125H-9375+260416)

$$0 = \frac { 2 } { 2 } H 125 + 10 ( 125 H - 9375 + 260416 )$$

Whakaoti mō H

$$H=-\frac{H_{125}}{1250}-\frac{251041}{125}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawehea te 2 ki te 2, kia riro ko 1.

$$0=1H_{125}+10\left(125H-9375+260416\right)$$

Tāpirihia te -9375 ki te 260416, ka 251041.

$$0=1H_{125}+10\left(125H+251041\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10 ki te 125H+251041.

$$0=1H_{125}+1250H+2510410$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1H_{125}+1250H+2510410=0$$

Tangohia te 1H_{125} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$1250H+2510410=-H_{125}$$

Tangohia te 2510410 mai i ngā taha e rua.

$$1250H=-H_{125}-2510410$$

Whakawehea ngā taha e rua ki te 1250.

$$\frac{1250H}{1250}=\frac{-H_{125}-2510410}{1250}$$

Mā te whakawehe ki te 1250 ka wetekia te whakareanga ki te 1250.

$$H=\frac{-H_{125}-2510410}{1250}$$

Whakawehe -H_{125}-2510410 ki te 1250.

$$H=-\frac{H_{125}}{1250}-\frac{251041}{125}$$

Whakaoti mō H_125

$$H_{125}=-1250H-2510410$$

Ngā Upane Otinga

Whakawehea te 2 ki te 2, kia riro ko 1.

$$0=1H_{125}+10\left(125H-9375+260416\right)$$

Tāpirihia te -9375 ki te 260416, ka 251041.

$$0=1H_{125}+10\left(125H+251041\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10 ki te 125H+251041.

$$0=1H_{125}+1250H+2510410$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1H_{125}+1250H+2510410=0$$

Tangohia te 1250H mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$1H_{125}+2510410=-1250H$$

Tangohia te 2510410 mai i ngā taha e rua.

$$1H_{125}=-1250H-2510410$$

Whakaraupapatia anō ngā kīanga tau.

$$H_{125}=-1250H-2510410$$