Whakaoti i te -4-2x^2=-2

$$-4-2 { x }^{ 2 } =-2$$

Whakaoti mō x (complex solution)

$$x=-i$$

$$x=i$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 4 ki ngā taha e rua.

$$-2x^{2}=-2+4$$

Tāpirihia te -2 ki te 4, ka 2.

$$-2x^{2}=2$$

Whakawehea ngā taha e rua ki te -2.

$$x^{2}=\frac{2}{-2}$$

Whakawehea te 2 ki te -2, kia riro ko -1.

$$x^{2}=-1$$

Kua oti te whārite te whakatau.

$$x=i x=-i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 2 ki ngā taha e rua.

$$-4-2x^{2}+2=0$$

Tāpirihia te -4 ki te 2, ka -2.

$$-2-2x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-2x^{2}-2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -2 mō a, 0 mō b, me -2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2\right)\left(-2\right)}}{2\left(-2\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-2\right)\left(-2\right)}}{2\left(-2\right)}$$

Whakareatia -4 ki te -2.

$$x=\frac{0±\sqrt{8\left(-2\right)}}{2\left(-2\right)}$$

Whakareatia 8 ki te -2.

$$x=\frac{0±\sqrt{-16}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te -16.

$$x=\frac{0±4i}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$x=\frac{0±4i}{-4}$$

Nā, me whakaoti te whārite x=\frac{0±4i}{-4} ina he tāpiri te ±.

$$x=-i$$

Nā, me whakaoti te whārite x=\frac{0±4i}{-4} ina he tango te ±.

$$x=i$$

Kua oti te whārite te whakatau.

$$x=-i x=i$$