Whakaoti i te -3(x-2)+15leq5

$$-3(x-2)+15 \leq 5$$

Whakaoti mō x

$$x\geq \frac{16}{3}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x-2.

$$-3x+6+15\leq 5$$

Tāpirihia te 6 ki te 15, ka 21.

$$-3x+21\leq 5$$

Tangohia te 21 mai i ngā taha e rua.

$$-3x\leq 5-21$$

Tangohia te 21 i te 5, ka -16.

$$-3x\leq -16$$

Whakawehea ngā taha e rua ki te -3. I te mea he tōraro a -3, ka huri te ahunga koreōrite.

$$x\geq \frac{-16}{-3}$$

Ka taea te hautanga \frac{-16}{-3} te whakamāmā ki te \frac{16}{3} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x\geq \frac{16}{3}$$