Whakaoti i te -2x^2=1

$$-2 { x }^{ 2 } =1$$

Whakaoti mō x (complex solution)

$$x=-\frac{\sqrt{2}i}{2}\approx -0-0.707106781i$$

$$x=\frac{\sqrt{2}i}{2}\approx 0.707106781i$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te -2.

$$x^{2}=-\frac{1}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{2}i}{2} x=-\frac{\sqrt{2}i}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te -2.

$$x^{2}=-\frac{1}{2}$$

Me tāpiri te \frac{1}{2} ki ngā taha e rua.

$$x^{2}+\frac{1}{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me \frac{1}{2} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times \frac{1}{2}}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times \frac{1}{2}}}{2}$$

Whakareatia -4 ki te \frac{1}{2}.

$$x=\frac{0±\sqrt{-2}}{2}$$

Tuhia te pūtakerua o te -2.

$$x=\frac{0±\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{2}i}{2} ina he tāpiri te ±.

$$x=\frac{\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{2}i}{2} ina he tango te ±.

$$x=-\frac{\sqrt{2}i}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{2}i}{2} x=-\frac{\sqrt{2}i}{2}$$