Whakaoti i te -2x^2/3-8x/3+10/3

$$-2 \frac{ { x }^{ 2 } }{ 3 } -8 \frac{ x }{ 3 } + \frac{ 10 }{ 3 }$$

Aromātai

$$\frac{2\left(1-x\right)\left(x+5\right)}{3}$$

Ngā Hipanga Rongoā Poto

Tuhia te -2\times \frac{x^{2}}{3} hei hautanga kotahi.

$$\frac{-2x^{2}}{3}-8\times \frac{x}{3}+\frac{10}{3}$$

Tuhia te 8\times \frac{x}{3} hei hautanga kotahi.

$$\frac{-2x^{2}}{3}-\frac{8x}{3}+\frac{10}{3}$$

Tā te mea he rite te tauraro o \frac{-2x^{2}}{3} me \frac{8x}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-2x^{2}-8x}{3}+\frac{10}{3}$$

Tā te mea he rite te tauraro o \frac{-2x^{2}-8x}{3} me \frac{10}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-2x^{2}-8x+10}{3}$$

Tauwehe

$$\frac{2\left(1-x\right)\left(x+5\right)}{3}$$

Ngā Upane Otinga

Tauwehea te \frac{2}{3}.

$$\frac{2\left(-x^{2}-4x+5\right)}{3}$$

Whakaarohia te -x^{2}-4x+5. Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei -x^{2}+ax+bx+5. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-4 ab=-5=-5$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=1 b=-5$$

Tuhia anō te -x^{2}-4x+5 hei \left(-x^{2}+x\right)+\left(-5x+5\right).

$$\left(-x^{2}+x\right)+\left(-5x+5\right)$$

Tauwehea te x i te tuatahi me te 5 i te rōpū tuarua.

$$x\left(-x+1\right)+5\left(-x+1\right)$$

Whakatauwehea atu te kīanga pātahi -x+1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(-x+1\right)\left(x+5\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$\frac{2\left(-x+1\right)\left(x+5\right)}{3}$$