Whakaoti i te -1-2x^2=-2

$$-1-2 { x }^{ 2 } =-2$$

Whakaoti mō x

$$x=\frac{\sqrt{2}}{2}\approx 0.707106781$$

$$x=-\frac{\sqrt{2}}{2}\approx -0.707106781$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 1 ki ngā taha e rua.

$$-2x^{2}=-2+1$$

Tāpirihia te -2 ki te 1, ka -1.

$$-2x^{2}=-1$$

Whakawehea ngā taha e rua ki te -2.

$$x^{2}=\frac{-1}{-2}$$

Ka taea te hautanga \frac{-1}{-2} te whakamāmā ki te \frac{1}{2} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x^{2}=\frac{1}{2}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 2 ki ngā taha e rua.

$$-1-2x^{2}+2=0$$

Tāpirihia te -1 ki te 2, ka 1.

$$1-2x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-2x^{2}+1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -2 mō a, 0 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2\right)}}{2\left(-2\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-2\right)}}{2\left(-2\right)}$$

Whakareatia -4 ki te -2.

$$x=\frac{0±\sqrt{8}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te 8.

$$x=\frac{0±2\sqrt{2}}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$x=\frac{0±2\sqrt{2}}{-4}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}}{-4} ina he tāpiri te ±.

$$x=-\frac{\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}}{-4} ina he tango te ±.

$$x=\frac{\sqrt{2}}{2}$$

Kua oti te whārite te whakatau.

$$x=-\frac{\sqrt{2}}{2} x=\frac{\sqrt{2}}{2}$$