Whakaoti i te -(x+1)(-1)(x-1)=8

$$-(x+1)(-1)(x-1)=8$$

Whakaoti mō x

$$x=-3$$

$$x=3$$

Ngā Upane mā te Kimi Pūtakerua

Hei kimi i te tauaro o x+1, kimihia te tauaro o ia taurangi.

$$\left(-x-1\right)\left(-1\right)\left(x-1\right)=8$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x-1 ki te -1.

$$\left(x+1\right)\left(x-1\right)=8$$

Whakaarohia te \left(x+1\right)\left(x-1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-1^{2}=8$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$x^{2}-1=8$$

Me tāpiri te 1 ki ngā taha e rua.

$$x^{2}=8+1$$

Tāpirihia te 8 ki te 1, ka 9.

$$x^{2}=9$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=3 x=-3$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Hei kimi i te tauaro o x+1, kimihia te tauaro o ia taurangi.

$$\left(-x-1\right)\left(-1\right)\left(x-1\right)=8$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x-1 ki te -1.

$$\left(x+1\right)\left(x-1\right)=8$$

Whakaarohia te \left(x+1\right)\left(x-1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-1^{2}=8$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$x^{2}-1=8$$

Tangohia te 8 mai i ngā taha e rua.

$$x^{2}-1-8=0$$

Tangohia te 8 i te -1, ka -9.

$$x^{2}-9=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -9 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

Whakareatia -4 ki te -9.

$$x=\frac{0±\sqrt{36}}{2}$$

Tuhia te pūtakerua o te 36.

$$x=\frac{0±6}{2}$$

Nā, me whakaoti te whārite x=\frac{0±6}{2} ina he tāpiri te ±. Whakawehe 6 ki te 2.

$$x=3$$

Nā, me whakaoti te whārite x=\frac{0±6}{2} ina he tango te ±. Whakawehe -6 ki te 2.

$$x=-3$$

Kua oti te whārite te whakatau.

$$x=3 x=-3$$