Whakaoti i te -(-3(-2(x+5-6x)-2x)-3)=x

$$-(-3(-2(x+5-6x)-2x)-3)=x$$

Whakaoti mō x

$$x = \frac{27}{23} = 1\frac{4}{23} \approx 1.173913043$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te x me -6x, ka -5x.

$$-\left(-3\left(-2\left(-5x+5\right)-2x\right)-3\right)=x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te -5x+5.

$$-\left(-3\left(10x-10-2x\right)-3\right)=x$$

Pahekotia te 10x me -2x, ka 8x.

$$-\left(-3\left(8x-10\right)-3\right)=x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 8x-10.

$$-\left(-24x+30-3\right)=x$$

Tangohia te 3 i te 30, ka 27.

$$-\left(-24x+27\right)=x$$

Hei kimi i te tauaro o -24x+27, kimihia te tauaro o ia taurangi.

$$-\left(-24x\right)-27=x$$

Ko te tauaro o -24x ko 24x.

$$24x-27=x$$

Tangohia te x mai i ngā taha e rua.

$$24x-27-x=0$$

Pahekotia te 24x me -x, ka 23x.

$$23x-27=0$$

Me tāpiri te 27 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$23x=27$$

Whakawehea ngā taha e rua ki te 23.

$$x=\frac{27}{23}$$