Whakaoti i te -f*-6*0.6=1/2*0.6*10*0.3-1/2*0.6*16

$$- f \cdot - 6 \times 0.6 = \frac { 1 } { 2 } \times 0.6 \times 10 \times 0.3 - \frac { 1 } { 2 } \times 0.6 \times 16$$

Whakaoti mō f

$$f = -\frac{13}{12} = -1\frac{1}{12} \approx -1.083333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te -6 ki te 0.6, ka -3.6.

$$\left(-f\right)\left(-3.6\right)=\frac{1}{2}\times 0.6\times 10\times 0.3-\frac{1}{2}\times 0.6\times 16$$

Me tahuri ki tau ā-ira 0.6 ki te hautau \frac{6}{10}. Whakahekea te hautanga \frac{6}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\left(-f\right)\left(-3.6\right)=\frac{1}{2}\times \frac{3}{5}\times 10\times 0.3-\frac{1}{2}\times 0.6\times 16$$

Me whakarea te \frac{1}{2} ki te \frac{3}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\left(-f\right)\left(-3.6\right)=\frac{1\times 3}{2\times 5}\times 10\times 0.3-\frac{1}{2}\times 0.6\times 16$$

Mahia ngā whakarea i roto i te hautanga \frac{1\times 3}{2\times 5}.

$$\left(-f\right)\left(-3.6\right)=\frac{3}{10}\times 10\times 0.3-\frac{1}{2}\times 0.6\times 16$$

Me whakakore te 10 me te 10.

$$\left(-f\right)\left(-3.6\right)=3\times 0.3-\frac{1}{2}\times 0.6\times 16$$

Whakareatia te 3 ki te 0.3, ka 0.9.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{1}{2}\times 0.6\times 16$$

Me tahuri ki tau ā-ira 0.6 ki te hautau \frac{6}{10}. Whakahekea te hautanga \frac{6}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{1}{2}\times \frac{3}{5}\times 16$$

Me whakarea te \frac{1}{2} ki te \frac{3}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{1\times 3}{2\times 5}\times 16$$

Mahia ngā whakarea i roto i te hautanga \frac{1\times 3}{2\times 5}.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{3}{10}\times 16$$

Tuhia te \frac{3}{10}\times 16 hei hautanga kotahi.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{3\times 16}{10}$$

Whakareatia te 3 ki te 16, ka 48.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{48}{10}$$

Whakahekea te hautanga \frac{48}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\left(-f\right)\left(-3.6\right)=0.9-\frac{24}{5}$$

Me tahuri ki tau ā-ira 0.9 ki te hautau \frac{9}{10}.

$$\left(-f\right)\left(-3.6\right)=\frac{9}{10}-\frac{24}{5}$$

Ko te maha noa iti rawa atu o 10 me 5 ko 10. Me tahuri \frac{9}{10} me \frac{24}{5} ki te hautau me te tautūnga 10.

$$\left(-f\right)\left(-3.6\right)=\frac{9}{10}-\frac{48}{10}$$

Tā te mea he rite te tauraro o \frac{9}{10} me \frac{48}{10}, me tango rāua mā te tango i ō raua taurunga.

$$\left(-f\right)\left(-3.6\right)=\frac{9-48}{10}$$

Tangohia te 48 i te 9, ka -39.

$$\left(-f\right)\left(-3.6\right)=-\frac{39}{10}$$

Whakawehea ngā taha e rua ki te -3.6.

$$-f=\frac{-\frac{39}{10}}{-3.6}$$

Tuhia te \frac{-\frac{39}{10}}{-3.6} hei hautanga kotahi.

$$-f=\frac{-39}{10\left(-3.6\right)}$$

Whakareatia te 10 ki te -3.6, ka -36.

$$-f=\frac{-39}{-36}$$

Whakahekea te hautanga \frac{-39}{-36} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -3.

$$-f=\frac{13}{12}$$

Me whakarea ngā taha e rua ki te -1.

$$f=-\frac{13}{12}$$