Whakaoti i te -b^2x^2+ax+4=0

$$- b ^ { 2 } x ^ { 2 } + a x + 4 = 0$$

Whakaoti mō a

$$a=\frac{\left(bx\right)^{2}-4}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \left(-b^{2}\right)x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$ax+4=-\left(-b^{2}\right)x^{2}$$

Tangohia te 4 mai i ngā taha e rua.

$$ax=-\left(-b^{2}\right)x^{2}-4$$

Whakareatia te -1 ki te -1, ka 1.

$$ax=b^{2}x^{2}-4$$

He hanga arowhānui tō te whārite.

$$xa=b^{2}x^{2}-4$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xa}{x}=\frac{b^{2}x^{2}-4}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$a=\frac{b^{2}x^{2}-4}{x}$$

Whakawehe b^{2}x^{2}-4 ki te x.

$$a=xb^{2}-\frac{4}{x}$$

Whakaoti mō b (complex solution)

$$b=-\frac{\sqrt{ax+4}}{x}$$

$$b=\frac{\sqrt{ax+4}}{x}\text{, }x\neq 0$$

Whakaoti mō b

$$b=\frac{\sqrt{ax+4}}{|x|}$$

$$b=-\frac{\sqrt{ax+4}}{|x|}\text{, }\left(a\neq 0\text{ and }x=-\frac{4}{a}\right)\text{ or }\left(x\leq -\frac{4}{a}\text{ and }a\leq 0\text{ and }x\neq 0\right)\text{ or }\left(a\geq 0\text{ and }x\geq -\frac{4}{a}\text{ and }x\neq 0\right)\text{ or }\left(a=0\text{ and }x\neq 0\right)$$