Whakaoti i te -a=sqrt{2a^2-3ab}

$$- a = \sqrt { 2 a ^ { 2 } - 3 a b }$$

Whakaoti mō b

$$\left\{\begin{matrix}b=\frac{a}{3}\text{, }&a\leq 0\\b\in \mathrm{R}\text{, }&a=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{2a^{2}-3ab}=-a$$

Pūruatia ngā taha e rua o te whārite.

$$\left(-3a\right)b+2a^{2}=a^{2}$$

Me tango 2a^{2} mai i ngā taha e rua o te whārite.

$$\left(-3a\right)b+2a^{2}-2a^{2}=a^{2}-2a^{2}$$

Mā te tango i te 2a^{2} i a ia ake anō ka toe ko te 0.

$$\left(-3a\right)b=a^{2}-2a^{2}$$

Tango 2a^{2} mai i a^{2}.

$$\left(-3a\right)b=-a^{2}$$

Whakawehea ngā taha e rua ki te -3a.

$$\frac{\left(-3a\right)b}{-3a}=-\frac{a^{2}}{-3a}$$

Mā te whakawehe ki te -3a ka wetekia te whakareanga ki te -3a.

$$b=-\frac{a^{2}}{-3a}$$

Whakawehe -a^{2} ki te -3a.

$$b=\frac{a}{3}$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}\\a=0\text{, }&\text{unconditionally}\\a=3b\text{, }&arg(b)\geq \pi \text{ or }b=0\end{matrix}\right.$$

Whakaoti mō b (complex solution)

$$\left\{\begin{matrix}b=\frac{a}{3}\text{, }&arg(a)\geq \pi \text{ or }a=0\\b\in \mathrm{C}\text{, }&a=0\end{matrix}\right.$$

Whakaoti mō a

$$\left\{\begin{matrix}\\a=0\text{, }&\text{unconditionally}\\a=3b\text{, }&b\leq 0\end{matrix}\right.$$