Whakaoti i te -8x^4:(-4x^3)=

$$- 8 x ^ { 4 } : ( - 4 x ^ { 3 } ) =$$

Aromātai

$$2x$$

Ngā Upane mō te Hua o ngā Pānga Taupū e Rua

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(-8x^{4}\right)^{1}\times \frac{1}{-4x^{3}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$\left(-8\right)^{1}\left(x^{4}\right)^{1}\times \frac{1}{-4}\times \frac{1}{x^{3}}$$

Whakamahia te Āhuatanga Kōaro o te Whakareanga.

$$\left(-8\right)^{1}\times \frac{1}{-4}\left(x^{4}\right)^{1}\times \frac{1}{x^{3}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$\left(-8\right)^{1}\times \frac{1}{-4}x^{4}x^{3\left(-1\right)}$$

Whakareatia 3 ki te -1.

$$\left(-8\right)^{1}\times \frac{1}{-4}x^{4}x^{-3}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\left(-8\right)^{1}\times \frac{1}{-4}x^{4-3}$$

Tāpirihia ngā taupū 4 me -3.

$$\left(-8\right)^{1}\times \frac{1}{-4}x^{1}$$

Hīkina te -8 ki te pū 1.

$$-8\times \frac{1}{-4}x^{1}$$

Hīkina te -4 ki te pū -1.

$$-8\left(-\frac{1}{4}\right)x^{1}$$

Whakareatia -8 ki te -\frac{1}{4}.

$$2x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$2x$$

Ngā Upane mō te Otinga o ngā Pānga Taupū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{\left(-8\right)^{1}x^{4}}{\left(-4\right)^{1}x^{3}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\left(-8\right)^{1}x^{4-3}}{\left(-4\right)^{1}}$$

Tango 3 mai i 4.

$$\frac{\left(-8\right)^{1}x^{1}}{\left(-4\right)^{1}}$$

Whakawehe -8 ki te -4.

$$2x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$2x$$

Kimi Pārōnaki e ai ki x

$$2$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(-\frac{8}{-4}\right)x^{4-3})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2x^{1-1}$$

Mahia ngā tātaitanga.

$$2x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$2\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$2$$