Whakaoti i te -6x_{1}+5x_{2}=20

$$- 6 x _ { 1 } + 5 x _ { 2 } = 20$$

Whakaoti mō x_1

$$x_{1}=\frac{5\left(x_{2}-4\right)}{6}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 5x_{2} mai i ngā taha e rua.

$$-6x_{1}=20-5x_{2}$$

Whakawehea ngā taha e rua ki te -6.

$$\frac{-6x_{1}}{-6}=\frac{20-5x_{2}}{-6}$$

Mā te whakawehe ki te -6 ka wetekia te whakareanga ki te -6.

$$x_{1}=\frac{20-5x_{2}}{-6}$$

Whakawehe 20-5x_{2} ki te -6.

$$x_{1}=\frac{5x_{2}}{6}-\frac{10}{3}$$

Whakaoti mō x_2

$$x_{2}=\frac{6x_{1}}{5}+4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te 6x_{1} ki ngā taha e rua.

$$5x_{2}=20+6x_{1}$$

He hanga arowhānui tō te whārite.

$$5x_{2}=6x_{1}+20$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{5x_{2}}{5}=\frac{6x_{1}+20}{5}$$

Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.

$$x_{2}=\frac{6x_{1}+20}{5}$$

Whakawehe 20+6x_{1} ki te 5.

$$x_{2}=\frac{6x_{1}}{5}+4$$