Whakaoti i te -5(v+1)=3v-6+2(5v+8)

$$- 5 ( v + 1 ) = 3 v - 6 + 2 ( 5 v + 8 )$$

Whakaoti mō v

$$v=-\frac{5}{6}\approx -0.833333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te v+1.

$$-5v-5=3v-6+2\left(5v+8\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 5v+8.

$$-5v-5=3v-6+10v+16$$

Pahekotia te 3v me 10v, ka 13v.

$$-5v-5=13v-6+16$$

Tāpirihia te -6 ki te 16, ka 10.

$$-5v-5=13v+10$$

Tangohia te 13v mai i ngā taha e rua.

$$-5v-5-13v=10$$

Pahekotia te -5v me -13v, ka -18v.

$$-18v-5=10$$

Me tāpiri te 5 ki ngā taha e rua.

$$-18v=10+5$$

Tāpirihia te 10 ki te 5, ka 15.

$$-18v=15$$

Whakawehea ngā taha e rua ki te -18.

$$v=\frac{15}{-18}$$

Whakahekea te hautanga \frac{15}{-18} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$v=-\frac{5}{6}$$