Whakaoti i te -3x^2-6x+9

$$- 3 x ^ { 2 } - 6 x + 9$$

Tauwehe

$$3\left(1-x\right)\left(x+3\right)$$

Ngā Upane Otinga

Tauwehea te 3.

$$3\left(-x^{2}-2x+3\right)$$

Whakaarohia te -x^{2}-2x+3. Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei -x^{2}+ax+bx+3. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-2 ab=-3=-3$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=1 b=-3$$

Tuhia anō te -x^{2}-2x+3 hei \left(-x^{2}+x\right)+\left(-3x+3\right).

$$\left(-x^{2}+x\right)+\left(-3x+3\right)$$

Tauwehea te x i te tuatahi me te 3 i te rōpū tuarua.

$$x\left(-x+1\right)+3\left(-x+1\right)$$

Whakatauwehea atu te kīanga pātahi -x+1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(-x+1\right)\left(x+3\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$3\left(-x+1\right)\left(x+3\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-3x^{2}-6x+9=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\left(-3\right)\times 9}}{2\left(-3\right)}$$

Pūrua -6.

$$x=\frac{-\left(-6\right)±\sqrt{36-4\left(-3\right)\times 9}}{2\left(-3\right)}$$

Whakareatia -4 ki te -3.

$$x=\frac{-\left(-6\right)±\sqrt{36+12\times 9}}{2\left(-3\right)}$$

Whakareatia 12 ki te 9.

$$x=\frac{-\left(-6\right)±\sqrt{36+108}}{2\left(-3\right)}$$

Tāpiri 36 ki te 108.

$$x=\frac{-\left(-6\right)±\sqrt{144}}{2\left(-3\right)}$$

Tuhia te pūtakerua o te 144.

$$x=\frac{-\left(-6\right)±12}{2\left(-3\right)}$$

Ko te tauaro o -6 ko 6.

$$x=\frac{6±12}{2\left(-3\right)}$$

Whakareatia 2 ki te -3.

$$x=\frac{6±12}{-6}$$

Nā, me whakaoti te whārite x=\frac{6±12}{-6} ina he tāpiri te ±. Tāpiri 6 ki te 12.

$$x=\frac{18}{-6}$$

Whakawehe 18 ki te -6.

$$x=-3$$

Nā, me whakaoti te whārite x=\frac{6±12}{-6} ina he tango te ±. Tango 12 mai i 6.

$$x=-\frac{6}{-6}$$

Whakawehe -6 ki te -6.

$$x=1$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -3 mō te x_{1} me te 1 mō te x_{2}.

$$-3x^{2}-6x+9=-3\left(x-\left(-3\right)\right)\left(x-1\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$-3x^{2}-6x+9=-3\left(x+3\right)\left(x-1\right)$$

Aromātai

$$3\left(1-x\right)\left(x+3\right)$$