Whakaoti i te -3m^2+m

$$- 3 m ^ { 2 } + m$$

Tauwehe

$$m\left(1-3m\right)$$

Ngā Upane Otinga

Tauwehea te m.

$$m\left(-3m+1\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-3m^{2}+m=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$m=\frac{-1±\sqrt{1^{2}}}{2\left(-3\right)}$$

Tuhia te pūtakerua o te 1^{2}.

$$m=\frac{-1±1}{2\left(-3\right)}$$

Whakareatia 2 ki te -3.

$$m=\frac{-1±1}{-6}$$

Nā, me whakaoti te whārite m=\frac{-1±1}{-6} ina he tāpiri te ±. Tāpiri -1 ki te 1.

$$m=\frac{0}{-6}$$

Whakawehe 0 ki te -6.

$$m=0$$

Nā, me whakaoti te whārite m=\frac{-1±1}{-6} ina he tango te ±. Tango 1 mai i -1.

$$m=-\frac{2}{-6}$$

Whakahekea te hautanga \frac{-2}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$m=\frac{1}{3}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te \frac{1}{3} mō te x_{2}.

$$-3m^{2}+m=-3m\left(m-\frac{1}{3}\right)$$

Tango \frac{1}{3} mai i m mā te kimi i te tauraro pātahi me te tango i ngā taurunga, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$-3m^{2}+m=-3m\times \frac{-3m+1}{-3}$$

Whakakorea atu te tauwehe pūnoa nui rawa 3 i roto i te -3 me te -3.

$$-3m^{2}+m=m\left(-3m+1\right)$$

Aromātai

$$m\left(1-3m\right)$$