Whakaoti i te -3^2+50div2^2*(-1/5)-1=

$$- 3 ^ { 2 } + 50 \div 2 ^ { 2 } \times ( - \frac { 1 } { 5 } ) - 1 =$$

Aromātai

$$-\frac{25}{2}=-12.5$$

Ngā Upane Otinga

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$-9+\frac{50}{2^{2}}\left(-\frac{1}{5}\right)-1$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$-9+\frac{50}{4}\left(-\frac{1}{5}\right)-1$$

Whakahekea te hautanga \frac{50}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$-9+\frac{25}{2}\left(-\frac{1}{5}\right)-1$$

Me whakarea te \frac{25}{2} ki te -\frac{1}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$-9+\frac{25\left(-1\right)}{2\times 5}-1$$

Mahia ngā whakarea i roto i te hautanga \frac{25\left(-1\right)}{2\times 5}.

$$-9+\frac{-25}{10}-1$$

Whakahekea te hautanga \frac{-25}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$-9-\frac{5}{2}-1$$

Me tahuri te -9 ki te hautau -\frac{18}{2}.

$$-\frac{18}{2}-\frac{5}{2}-1$$

Tā te mea he rite te tauraro o -\frac{18}{2} me \frac{5}{2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-18-5}{2}-1$$

Tangohia te 5 i te -18, ka -23.

$$-\frac{23}{2}-1$$

Me tahuri te 1 ki te hautau \frac{2}{2}.

$$-\frac{23}{2}-\frac{2}{2}$$

Tā te mea he rite te tauraro o -\frac{23}{2} me \frac{2}{2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-23-2}{2}$$

Tangohia te 2 i te -23, ka -25.

$$-\frac{25}{2}$$

Tauwehe

$$-\frac{25}{2} = -12\frac{1}{2} = -12.5$$