Whakaoti i te -2x^2-2x

$$- 2 x ^ { 2 } - 2 x$$

Tauwehe

$$-2x\left(x+1\right)$$

Ngā Upane Otinga

Tauwehea te 2.

$$2\left(-x^{2}-x\right)$$

Whakaarohia te -x^{2}-x. Tauwehea te x.

$$x\left(-x-1\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$2x\left(-x-1\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-2x^{2}-2x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te \left(-2\right)^{2}.

$$x=\frac{-\left(-2\right)±2}{2\left(-2\right)}$$

Ko te tauaro o -2 ko 2.

$$x=\frac{2±2}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$x=\frac{2±2}{-4}$$

Nā, me whakaoti te whārite x=\frac{2±2}{-4} ina he tāpiri te ±. Tāpiri 2 ki te 2.

$$x=\frac{4}{-4}$$

Whakawehe 4 ki te -4.

$$x=-1$$

Nā, me whakaoti te whārite x=\frac{2±2}{-4} ina he tango te ±. Tango 2 mai i 2.

$$x=\frac{0}{-4}$$

Whakawehe 0 ki te -4.

$$x=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -1 mō te x_{1} me te 0 mō te x_{2}.

$$-2x^{2}-2x=-2\left(x-\left(-1\right)\right)x$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$-2x^{2}-2x=-2\left(x+1\right)x$$

Aromātai

$$-2x\left(x+1\right)$$