Whakaoti i te -2ax+a^2+1=0

$$- 2 a x + a ^ { 2 } + 1 = 0$$

Whakaoti mō x

$$x=\frac{a}{2}+\frac{1}{2a}$$

$$a\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te a^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2ax+1=-a^{2}$$

Tangohia te 1 mai i ngā taha e rua.

$$-2ax=-a^{2}-1$$

He hanga arowhānui tō te whārite.

$$\left(-2a\right)x=-a^{2}-1$$

Whakawehea ngā taha e rua ki te -2a.

$$\frac{\left(-2a\right)x}{-2a}=\frac{-a^{2}-1}{-2a}$$

Mā te whakawehe ki te -2a ka wetekia te whakareanga ki te -2a.

$$x=\frac{-a^{2}-1}{-2a}$$

Whakawehe -a^{2}-1 ki te -2a.

$$x=\frac{a}{2}+\frac{1}{2a}$$

Whakaoti mō a (complex solution)

$$a=\sqrt{x^{2}-1}+x$$

$$a=-\sqrt{x^{2}-1}+x$$

Whakaoti mō a

$$a=\sqrt{x^{2}-1}+x$$

$$a=-\sqrt{x^{2}-1}+x\text{, }|x|\geq 1$$