Whakaoti i te -2a^2-a

$$- 2 a ^ { 2 } - a$$

Tauwehe

$$-a\left(2a+1\right)$$

Ngā Upane Otinga

Tauwehea te a.

$$a\left(-2a-1\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-2a^{2}-a=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$a=\frac{-\left(-1\right)±\sqrt{1}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te 1.

$$a=\frac{-\left(-1\right)±1}{2\left(-2\right)}$$

Ko te tauaro o -1 ko 1.

$$a=\frac{1±1}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$a=\frac{1±1}{-4}$$

Nā, me whakaoti te whārite a=\frac{1±1}{-4} ina he tāpiri te ±. Tāpiri 1 ki te 1.

$$a=\frac{2}{-4}$$

Whakahekea te hautanga \frac{2}{-4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$a=-\frac{1}{2}$$

Nā, me whakaoti te whārite a=\frac{1±1}{-4} ina he tango te ±. Tango 1 mai i 1.

$$a=\frac{0}{-4}$$

Whakawehe 0 ki te -4.

$$a=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -\frac{1}{2} mō te x_{1} me te 0 mō te x_{2}.

$$-2a^{2}-a=-2\left(a-\left(-\frac{1}{2}\right)\right)a$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$-2a^{2}-a=-2\left(a+\frac{1}{2}\right)a$$

Tāpiri \frac{1}{2} ki te a mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$-2a^{2}-a=-2\times \frac{-2a-1}{-2}a$$

Whakakorea atu te tauwehe pūnoa nui rawa 2 i roto i te -2 me te -2.

$$-2a^{2}-a=\left(-2a-1\right)a$$

Aromātai

$$-a\left(2a+1\right)$$