Whakaoti i te -2(x-2)^2=-8

$$- 2 ( x - 2 ) ^ { 2 } = - 8$$

Whakaoti mō x

$$x=4$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Whakawehea ngā taha e rua ki te -2.

$$\left(x-2\right)^{2}=\frac{-8}{-2}$$

Whakawehea te -8 ki te -2, kia riro ko 4.

$$\left(x-2\right)^{2}=4$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4=4$$

Tangohia te 4 mai i ngā taha e rua.

$$x^{2}-4x+4-4=0$$

Tangohia te 4 i te 4, ka 0.

$$x^{2}-4x=0$$

Tauwehea te x.

$$x\left(x-4\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te x-4=0.

$$x=0 x=4$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te -2.

$$\left(x-2\right)^{2}=\frac{-8}{-2}$$

Whakawehea te -8 ki te -2, kia riro ko 4.

$$\left(x-2\right)^{2}=4$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4=4$$

Tangohia te 4 mai i ngā taha e rua.

$$x^{2}-4x+4-4=0$$

Tangohia te 4 i te 4, ka 0.

$$x^{2}-4x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -4 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}}}{2}$$

Tuhia te pūtakerua o te \left(-4\right)^{2}.

$$x=\frac{-\left(-4\right)±4}{2}$$

Ko te tauaro o -4 ko 4.

$$x=\frac{4±4}{2}$$

Nā, me whakaoti te whārite x=\frac{4±4}{2} ina he tāpiri te ±. Tāpiri 4 ki te 4.

$$x=\frac{8}{2}$$

Whakawehe 8 ki te 2.

$$x=4$$

Nā, me whakaoti te whārite x=\frac{4±4}{2} ina he tango te ±. Tango 4 mai i 4.

$$x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=4 x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakawehea ngā taha e rua ki te -2.

$$\left(x-2\right)^{2}=\frac{-8}{-2}$$

Whakawehea te -8 ki te -2, kia riro ko 4.

$$\left(x-2\right)^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-2\right)^{2}}=\sqrt{4}$$

Whakarūnātia.

$$x-2=2 x-2=-2$$

Me tāpiri 2 ki ngā taha e rua o te whārite.

$$x=4 x=0$$